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Select a specific part of the string and print it

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# 1  
Old 11-30-2010
Select a specific part of the string and print it
Hi all,

I have a string that looks like:
Code:
#!/bin/sh

options="arguments: --user=alpha --group=beta --prefix=/usr/share --proxy-path=/proxy --proxy-tmp=/tmp --conf-path=/etc"

My goal is to transform the string into an array, then for each key, if it starts with "--proxy" to print the string after the equal sign:

Code:
#!/bin/sh

options=("arguments: --user=alpha --group=beta --prefix=/usr/share --proxy-path=/proxy --proxy-tmp=/tmp --conf-path=/etc")
for i in ${options[*]}; do
	if [ $i starts with "--proxy" ]; then
		option="the value present after the = sign"
		chmod 0755 $option
	fi
done

Thanks a lot for your help.
# 2  
Old 11-30-2010
Code:
awk -F'[" =]' '/proxy/{for(i=0;++i<=NF;){if($i ~ /--proxy/){system("chmod 0755 " $(i+1))}}}' file

# 3  
Old 11-30-2010
Standard sh dosn't support arrays, many linux flavours link /bin/sh to /bin/bash as this is probably what you have.

Your script is really close, a quick substring and delete from the from should get what you want:

Code:
#!/bin/bash
options=("arguments: --user=alpha --group=beta --prefix=/usr/share --proxy-path=/proxy --proxy-tmp=/tmp --conf-path=/etc")
for i in ${options[*]}; do
    if [ "${i:0:7}" = "--proxy" ]; then
        option=${i##*=} # the value present after the = sign"
        chmod 0755 $option
    fi
done

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