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find the line starting with a pattern and save a part in variable

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# 1  
Old 11-25-2010
find the line starting with a pattern and save a part in variable
Hi

i have a file which has mutiple line in it.

inside that i have a pattern similar to this

/abc/def/hij

i want to fine the pattern starting with "/" and get the first word in between the the symbols "/" i.e. "abc" in this case into a variable.


thanks in advance
# 2  
Old 11-25-2010
thru sed..
Code:
sed 's|^/\([^/]*\)/.*|\1|' inputfile > outfile

# 3  
Old 11-25-2010
or
Code:
echo "/test/test2/test4" | tr '/' ' ' | cut -f2 -d" "

# 4  
Old 11-25-2010
@research3: we could shorten it as
Code:
echo "/test/test2/test4" |  cut -f2 -d /

# 5  
Old 11-25-2010
that's true of corse!
# 6  
Old 11-25-2010
hello

thanks everyone

i have written code as

Code:
 
while read line; do
defaultStorage= `echo "/test/test2/test4/test6" | cut -f2 -d/`
echo $defaultStorage
done<defaultStore.txt


i am not getting the required result in defaultStorage
# 7  
Old 11-25-2010
there should be no space surrounding the = sign during variable assignment.So try as
Code:
defaultStorage=`echo "/test/test2/test4/test6" | cut -f2 -d/`
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