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Help: transform unix time format to standard

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# 1  
Old 11-17-2010
Help: transform unix time format to standard
Hello All,

Do you have any idea, how can I transform the unix time format to standard:

time_last_login=1268057983 Smilie

I would like to use the transformation in a AIX shell script Smilie
# 2  
Old 11-17-2010
Code:
$ perl -e "print scalar(localtime(1268057983))"
Mon Mar  8 15:19:43 2010

# 3  
Old 11-18-2010
Its works, thats cool, thanks Smilie

Its possible to do that without perl? Just for theoretically. Smilie
# 4  
Old 11-18-2010
By GNU date:

Code:
date -d @1268057983

by awk

Code:
awk 'BEGIN{print strftime("%Y-%m-%d",1268057983 )}'
2010-03-09

@cabrao
Seems we are in different time zone.
Last edited by rdcwayx; 11-18-2010 at 07:26 AM..
# 5  
Old 11-18-2010
The last two solutions are not working on AIX Smilie

date -d on AIX not a recognized flag

==========================================

and the
awk 'BEGIN{print strftime("%Y-%m-%d",1268057983 )}'
awk: 0602-553 Function strftime is not defined.
The source line number is 1.
# 6  
Old 11-18-2010
Another way would be to use the printf builtin of the kornshell 93.

Code:
$ printf "%(%a %Y-%m-%d %T)T\n" '#'1268057983
Mon 2010-03-08 15:19:43

# 7  
Old 11-22-2010
Would be good in simple ksh Smilie

Perl is good, but i think not all servers have perl package installed. Smilie
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