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[ask]date variable

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# 1  
Old 11-12-2010
[ask]date variable
Is there date variable in bash?

for example, I have string 01-23-2010 (mm-dd-yyyy) or 23-01-2010 (dd-mm-yyyy).
How can I convert that string to date variable?

and how to do some math operation based on date?
for example, today is 12-11-2010.
I want to know date 100 days after today or 50 days before today.
Is there any simple calculation to do that?
thanks
# 2  
Old 11-12-2010
The gnu date command does date arithmetic. There are no date datatypes in bash like there are in databases like Oracle.

If you look at the top bar on this page you will see "man pages". There is a linux man page for date. Try it.
# 3  
Old 11-12-2010
Quote:
Originally Posted by jim mcnamara
The gnu date command does date arithmetic. There are no date datatypes in bash like there are in databases like Oracle.

If you look at the top bar on this page you will see "man pages". There is a linux man page for date. Try it.
sorry, but I'm new to bash. I already read the manual, but I don't know how to use it..Smilie

How can I assign string to date?

I tried this command, but doesn't work..
Code:
start=$(date --utc --date "22-02-2010" "+%d-%m-%Y")

is there anything wrong with that command?
# 4  
Old 11-12-2010
Quote:
Originally Posted by 14th
...I tried this command, but doesn't work..
Code:
start=$(date --utc --date "22-02-2010" "+%d-%m-%Y")

is there anything wrong with that command?
Code:
$
$ start=$(date -u -d "22-Feb-2010")
$
$ echo $start
Mon Feb 22 00:00:00 UTC 2010
$

tyler_durden
This User Gave Thanks to durden_tyler For This Post:
14th
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