Hello, I'm new to UNIX and using BASH shell. Using VI to script and I can't figure this out. Basically, I'm trying to write a script that will ask for a filename, then ask for a name. It will then redirect this to a new file (whatever was choosen for the file name. These were my instructions:
Quote:
Make a copy of your sgen program called sgen2. Modify sgen2 to do the following: a. instead of using "sgen.out" as an output file name, sgen2 asks you for a file name and uses that name for its output file (see below). b. sgen2 asks you for your name and puts whatever you type in the output file along with the current date. c. sgen2 generates an output file with the name you typed that includes the following lines: (except for the --notes--):
#################################################### # Script: --the name of this file, see part 2a-- # Author: --your name, see part 2b-- # Date: --the date you ran the script, see part 2b-- #################################################### echo Hello, world\!\! echo I am the script $0
d. This output file is actually a Unix script. When you execute it, you should see this on the screen -- Hello, world!! I am the script whatever_you_called-it e. sgen2 checks to see if you don't give an output file name, in which case it displays the message "No script name" and stops, not generating the file. Likewise if you don't give it a value for your name, it should display "No name given" and stop. The sgen2 program should only generate its output file if you give both a file name and your name.
This is what I have so far.
Whenever I do this, the last like "I am the script $0" will display the original file name, that is sgen2, rather than the new filename. Any help would be GREATLY appreciated!
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