Shell Programming and Scripting

Let, I have three numbers

Code:

+00123.25
-00256.54
+00489.23

I need to sum up all those three numbers, after storing them in three variables (say var1, var2, var3).

I used both expr and BC, but they didn't work for me.
But, I am not able to sum up them, as I don't have any idea how to take those (+) and (-) sign in account while summing up.

try this:

Code:

a=00123.25
b=-00256.54
c=00489.23

Code:

echo " $a + $b + $c " | bc
355.94

I posted a simplified version to get the basic idea. Actually, I am reading those values from a file.
The datas are in the following format in a file (say result.txt):

Code:

+00000223.20
+00000451.40
+00000451.40
+00000213.20
+00000213.20
-00004135.50
+00001378.50

So, while reading these values in a loop I am not able to sum up the values.

Try this:

Code:

sum=$(awk '{s+=$0}END{printf("%.2f\n", s)}' file)
echo $sum

Thanks for all your prompt and valuable reponse.
But, in actual scenario, I have to read the data from the file using a while-do-done loop.
Each line I read from the file contains some data, from where I am using grep+cut to read some specific portion from few specific records.And, that specic portion contains those (+)ve and (-)ve values.

So, please let me know is it possible to sum up those numbers in the above scenario?

instead of using while/read and grep/cut, why don't use awk and do it ALL of it natively with one utility...

I ahve to use while/read and grep/cut...because before performing these arithmatic opertaion I need to do a lot more tasks on the source file.
So, if possible please suggest me how to do the arithmatic operation...while using the while/read and grep/cut.