awk to compare diff output by fields


 
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# 1  
Old 11-09-2010
awk to compare diff output by fields

Diff output as follows:

Code:
< AAA BBB CCC DDD EEE 123
> PPP QQQ RRR SSS TTT 111
> VVV WWW XXX YYY ZZZ 333
> AAA BBB CCC DDD EEE 124

How can i use awk to compare the last field to determine if the counter has increased, and need to ensure that the first 4 fields must have the same values, e.g. in the example above, the counter field has increased by 1 count for "AAA BBB CCC DDD EEE" entry.

Please advise and thanking you in advance.
# 2  
Old 11-10-2010
Quote:
Originally Posted by ux4me
Diff output as follows:

Code:
 
< AAA BBB CCC DDD EEE 123
> PPP QQQ RRR SSS TTT 111
> VVV WWW XXX YYY ZZZ 333
> AAA BBB CCC DDD EEE 124

How can i use awk to compare the last field to determine if the counter has increased, and need to ensure that the first 4 fields must have the same values, e.g. in the example above, the counter field has increased by 1 count for "AAA BBB CCC DDD EEE" entry.
...
So if the diff output is like so -

Code:
< AAA BBB CCC DDD EEE 123
> PPP QQQ RRR SSS TTT 111
> VVV WWW XXX YYY ZZZ 333
> AAA BBB CCC DDD EEE 124
> AAA BBB CCC DDD EEE 125
> PPP QQQ RRR SSS TTT 222
> PPP QQQ RRR SSS TTT 250
> AAA BBB CCC DDD EEE 129
> GGG HHH III JJJ KKK 111
> VVV WWW XXX YYY ZZZ 334

then should the counter be -

(a) 3, because "AAA BBB CCC DDD EEE" incremented 3 times?, or
(b) 2, because "PPP QQQ RRR SSS TTT" incremented 2 times?, or
(c) 1, because "VVV WWW XXX YYY ZZZ" incremented once?, or
(d) 0, because "GGG HHH III JJJ KKK" did not increment at all?

tyler_durden
# 3  
Old 11-10-2010
In your example, each entry will have it's own counter:

Code:
counter (a) = 3, because "AAA BBB CCC DDD EEE" incremented 3 times
counter (b) = 2, because "PPP QQQ RRR SSS TTT" incremented 2 times
counter (c) = 1, because "VVV WWW XXX YYY ZZZ" incremented once
counter (d) = 0, because "GGG HHH III JJJ KKK" did not increment at all

And based on the counter value, some actions will be triggered.
# 4  
Old 11-10-2010
Code:
nawk '{idx=$2 FS $3 FS $4 FS $5 FS $6;a[idx]++}END {for(i in a) print qq i qq " incremented " a[i]-1 " times"}' qq='"' diffOutputFile

# 5  
Old 11-10-2010
Thanks for the reply. I think I've confused some of us including myself. Let me try this again:

Diff output has this:
Code:
AAA BBB CCC DDD EEE 10
AAA BBB CCC DDD EEE 11
PPP QQQ RRR SSS TTT 5
PPP QQQ RRR SSS TTT 4
VVV WWW XXX YYY ZZZ 2

need some awk help to:
- scan the lines and compare the first 5 fields of each line
- and when all 5 fields match, then compare the 6th field (i.e. counter) to check if the value has increased or decreased
- if the counter value has increased, do something
- else, do nothing
- if scan cannot find line with matching first 5 fields, then do something
- end of scan

Thanks again in advance.. my apologies for the confusion.

Last edited by vgersh99; 11-10-2010 at 01:20 PM.. Reason: code tags, please!
# 6  
Old 11-10-2010
Code:
#!/bin/ksh

nawk '
  # create an variable "idx" which is a concatenation of the first 5 fields in a record/line
  # as we read the file line by line
  {idx=$1 FS $2 FS $3 FS $4 FS $5}
  {
    # see if "idx" is in array "a" - array "a" is indexed by the value of "idx"
    if (idx in a)
      # if "idx" is already in "a", check if the stored value (a[idx]) is less than the
      # last field ($NF) of the current record/line. If it's, we see the "increase" in value
      # If so, output the current line (print $0)
      if (a[idx]<$NF)
         print $0
    # store the last field ($NF) of the current record in aarray "a" indexed by "idx"
    a[idx]=$NF
  }' myDiffFile | while read line
do
  # read the output of "nawk" and do "doSomething" with the read line
  echo "doSomething with [$line]"
done


Last edited by vgersh99; 11-10-2010 at 01:54 PM.. Reason: comments
This User Gave Thanks to vgersh99 For This Post:
# 7  
Old 11-10-2010
wow.. i think it's working per your tip. do you mind explaining the code as i am trying to learn how to fish?

Thanks again.
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