Removing from beginning to first : using awk


 
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# 8  
Old 10-31-2010
Modified Scrutinizer's solution
Code:
awk '!/run2\.log:0\. /{sub(/[^:]*:[0-9]*\.[ \t]*/,x);print a++". " $0}' infile

# 9  
Old 10-31-2010
pravin27, there's something wrong with it, as it says

/run2: Event not found

I might have any number of runs there, not just run2.
# 10  
Old 10-31-2010
Try this,

Code:
awk '{if($0 !~ /run[0-9]+\.log:0\. /) {sub(/[^:]*:[0-9]*\.[ \t]*/,x);print a++". " $0}}' infile

# 11  
Old 10-31-2010
Seems better now
# 12  
Old 10-31-2010
Quote:
Originally Posted by kristinu
pravin27, there's something wrong with it, as it says

/run2: Event not found

I might have any number of runs there, not just run2.
That is probably because you left out single quotes and you are running it in bash which is trying to interpret the !-sign.
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