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Print each user at time

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# 1  
Old 10-30-2010
Print each user at time
I want to print each user at time and
I wrote :

Code:
cat /etc/passwd | grep "/home" | cut -d: -f > USERS
for USER in  `cat USERS` 
do 
echo "$user"
done

but it didn't work

thanks
Last edited by Scott; 10-30-2010 at 08:35 PM.. Reason: Code tags
# 2  
Old 10-30-2010
Quote:
Originally Posted by testman84
I want to print each user at time and
I wrote :

cat /etc/passwd | grep "/home" | cut -d: -f > USERS
for USER in `cat USERS`
do
echo "$user"
done

but it didn't work

thanks
where is field number Smilie
Code:
cut -d: -f ?

and is there any problem little?
Code:
for USER in `cat USERS`
echo "$user"

Last edited by ygemici; 10-30-2010 at 05:57 PM..
# 3  
Old 10-30-2010
sorry it is
Code:
cat /etc/passwd | grep "/home" | cut -d: -f1 > USERS

I forget to write in the post but i wrote it
but it don't work
Last edited by Scott; 10-30-2010 at 08:35 PM..
# 4  
Old 10-30-2010
Code:
cat /etc/passwd | grep "/home" | cut -d: -f1 > USERS
for user in `cat USERS`
 do
  echo "$user"
 done

Code:
for user in `grep "/home" /etc/passwd |cut -d: -f1`
 do
   echo "$user"
 done

This User Gave Thanks to ygemici For This Post:
testman84
# 5  
Old 10-30-2010
Quote:
Originally Posted by testman84
I want to print each user at time and
I wrote :

cat /etc/passwd | grep "/home" | cut -d: -f > USERS
for USER in `cat USERS`
do
echo "$user"
done

but it didn't work

thanks
Useless use of cat here: cat /etc/passwd | grep "/home"
Code:
grep "/home" /etc/passwd

does the same.

As ygemic mentioned, have a look at the variable names in your for statement. You echoing an empty variable.

I don't know why you redirect the output to a file
Code:
grep "/home" /etc/passwd | cut -d: -f1

does what you want.
This User Gave Thanks to pharyx For This Post:
testman84
# 6  
Old 10-30-2010
thanks it works
# 7  
Old 10-30-2010
all in one.

Code:
awk -F":" '/\/home/{print $1}' /etc/passwd
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