awk script problem

10-28-2010

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awk script problem

Hi,
How to check status of the files in the awk script
i am having two awk script in one bash script.Like
-BELOW is the exact structure of the script
script name: new.sh

Code:

{
awk -v v1=`.....`
{
if (){
  exit -1;
    }
  }
}
}'$file name1
 
{
awk -v  v2=`.....`
{
   if (){ 
       exit -1;
        } 
    }
}'$file name2
 
}

--> Now in the above script i need use exit -1; for checkin the status
--> What happans while testing 2nd awk gives the final status always.
-->For example new.sh script use to check error records , if first awk means v1 has error status should be -1
if 2nd awk v2 has error then status should -1
--> If v1 has error and v2 doesnt have the status is 0 that means its not taking exit -1;
--> if v2 has error and v1 doesnt have then status is -1
--> I want to check the if any of the awk check error then status should be give as -1; if no error then status hould be 0

Thanks & Regards,
Ganesh

Moderator's Comments:

Use code tags, please...

Last edited by Scott; 10-28-2010 at 10:22 AM..

Ganesh Khandare

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10-28-2010

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You would need to check the exit status code $? in the script after each awk program has run. It only has a range of 0 to 255, so -1 isn't a valid value.

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Do you need to execute the 2nd awk if the 1st fails?

if not use exit 1 for errors, and try:

Code:

 awk -v v1='....' { ... exit 1 ...}' $file_name1 && awk -v v2='....' { ... exit 1 ...}' $file_name2

if you still want to execute 2nd awk if the 1st fails:

Code:

awk -v v1='...' $file_name
exit_code1=$?
awk -v v2='...' $file_name2
let exit_code=$exit_code+$?

exit_code will be 1 if A or B fails and 2 if both fail (adjust logic as you need).

Last edited by Chubler_XL; 10-28-2010 at 11:35 PM.. Reason: Typos

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10-29-2010

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Sorry its wont work,noeed something else

Hi, As you said its ok ,but this is only one script . i am using two awk commands in one bash shell script. i am running script like
./script name.sh param1 param2

Here i am executing single script.
Now in this awk will work individually , after 1st awk over 2 nd will start to execute. Now i just wanted to know can i check status usinf if () condition.

like in 1st awk if error persent it will print error msg in 2nd awk also,

Now if 1st awk has error and 2nd awk dont then it should return staus as fail thant means it if i use echo $? on unix box it should give some value if no error present then after using echo $? it returns 0.

could you please give some solution for this.
or Shall put whole script for you referance.
Please reply,,

Thanks,
Ganesh

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Try...

Code:

awk ' ... ' #--awk program # 1
if [ $? -ne 0 ]
then
    echo "awk # 1 not okay"
else
    echo "awk # 1 okay"
    awk ' ... ' #--awk program # 2
    if [ $? -ne 0 ]
    then
        echo "awk # 2 not okay"
    else
        echo "awk # 2 okay"
    fi
fi

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Ok for the following script need status

Hi,
I dont need message to be print over there, need to exit the script if the file has error. i am putting my script below.
-> if i execute the script if the file has error it will go to if(n!=v1) condition now i need whenever it will go to if condtion after process all it should exit.
-> for checking status i'll use echo $? if error in file then it will return some value if not then returns 0

my script

Code:

{
nawk -v v1=`grep "$1_$2_CASHFLOW_FLD_COUNT" $propfile | cut -d"=" -f2` -F\" '{
      for(i=1;i<=NF;i+=2){
      n+=gsub("~","",$i)
  }
  if(n!=v1){
    print "Error in CASHFLOW_HANDOFF at line number " NR ", present  tilde count= " n
    print "Total Number Of Fields   = "v1+1
    print "Actual Tilde count= " v1
    print"cashflow_status=Fail"
}
   n=0
   
   }'  $va
}

--> i need to use exit -1; in the script to abord the script .if i use exit -1 in if (n!=v1) it will work for one record only if in file more than 2 rows having error then it wont work. Could you plz reply on that.
Thanks,
Ganesh.

Last edited by Franklin52; 10-29-2010 at 09:00 AM.. Reason: Please use code tags

Ganesh Khandare

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Shell Programming and Scripting