using sed


 
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# 1  
Old 10-26-2010
using sed

Please explain the following sed command
Code:
sed -n -e '/^------/,/^+-----/ !d' -e '/--------/ !p filename

getting output = 0


sample file
Code:
BTEQ 12.00.00.00 Tue Oct 26 21:22:19 2010
+---------+---------+---------+---------+---------+---------+---------+----
 .logon teradata.gdw.cba/chandna,
 *** Logon successfully completed.
 *** Teradata Database Release is 12.00.03.08
 *** Teradata Database Version is 12.00.03.14a
 *** Transaction Semantics are BTET.
 *** Character Set Name is 'ASCII'.
 *** New current role accepted.
 *** Total elapsed time was 1 second.
 
 *** Total elapsed time was 1 second.
+---------+---------+---------+---------+---------+---------+---------+----
.SET ECHOREQ OFF
+---------+---------+---------+---------+---------+---------+---------+----
+---------+---------+---------+---------+---------+---------+---------+----
 *** Query completed. One row found. One column returned.
 *** Total elapsed time was 1 second.
   Count(*)
-----------
          0
+---------+---------+---------+---------+---------+---------+---------+----
 *** You are now logged off from the DBC.
 *** Exiting BTEQ...
 *** RC (return code) = 0


Last edited by Scott; 10-26-2010 at 08:04 AM.. Reason: Please use code tags
# 2  
Old 10-26-2010
It the left part of the sed statement will print everything between and including a line that starts with "------" and one that starts with "+-----". So that would be:
Code:
-----------
0
+---------+---------+---------+---------+---------+---------+---------+----

The right side says that lines that contain "--------" should not get printed. So that leaves:
Code:
0

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