That message should be coming from elsewhere in your script (a [ ] test ). What happens if you run the awk statement on the command line without the "$@" ?
I am not able to write it into command line... In the middle of statement it just start from the beginning... I tried to rewrite it mannualy but it was same...
Well, i finnaly write it there, but nothing happens... I must press ctrl+c...
---------- Post updated at 09:47 PM ---------- Previous update was at 09:33 PM ----------
ok, when i write it into cmd line, the normal output goes out...
---------- Post updated 10-27-10 at 11:59 AM ---------- Previous update was 10-26-10 at 09:47 PM ----------
Well, i don't find any error in statement... What could be easier? To set whole awk command as a variable and in that case should awk print the line number, length of line and line, or to write whole output in awk like you posted before?
I would take a look at test statements [ .. ] in your shell script. Probably you left out a quote or forgot to put spaces around the [ and ] or around the = .
This User Gave Thanks to Scrutinizer For This Post:
I think, that simplier is to write it with awk...
But i have another problem with it... I need to fix arguments incoming to the script. The argument can't be empty, non exist, it must be text file... My suggestion is:
Code:
function print_help ()
{
echo "[-h]: print help"
}
if [ $1 = -h ]; then
print_help
exit 0
fi
if [ ! -e $@ ]; then
echo "Error: $@ doesn't exist" >/dev/stderr
exit 1
fi
if [ ! -s $@ ]; then
echo "Error: $@ is empty" >/dev/stderr
exit 1
fi
if [ -d $@ ]; then
echo "Error: $@ is directory" >/dev/stderr
exit 1
fi
if [ -f $@ ]; then
find $@ -type -f -exec file {} \; | grep "text"
echo "Error: $@ not text file" >/dev/stderr
exit 1
fi
But i have awk code after that and no argument get to him... How should i fix it?
---------- Post updated at 01:09 PM ---------- Previous update was at 01:07 PM ----------
Second throught is :
Code:
while [ 0 -lt $# ]; do
if [ $1 = -h ]; then
print_help
exit 0
fi
if [ ! -e $@ ]; then
echo "Error: $@ doesn't exist" >/dev/stderr
exit 1
fi
if [ ! -s $@ ]; then
echo "Error: $@ empty" >/dev/stderr
exit 1
fi
if [ -d $@ ]; then
echo "Error: $@ is directory" >/dev/stderr
exit 1
fi
shift
done
But there is same problem... No argument left for awk and therefore awko won't work
---------- Post updated at 03:33 PM ---------- Previous update was at 01:09 PM ----------
There is only one = in code...
Code:
if [ $1 = -h ]; then
Should i use -eq instead? and what above that testing of the files incoming to my script, can you help me with that?
---------- Post updated at 04:33 PM ---------- Previous update was at 03:33 PM ----------
Hello,
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Hi ,
i have a file with data as below.This is same file. But actual file contains to many rows.
i want to search for a string "Field 039 00" and delete that line and previous 3 lines in that file.. Can some body suggested me how can i do using either sed or awk command ?
Field 004... (7 Replies)
I want to find common line in two files and replace the next line of first file with the next line of second file. (sed,awk,perl,bash any solution is welcomed ) Case Ignored. Multiple Occurrence of same line.
File 1:
hgacdavd
sndm,ACNMSDC
msgid "Rome"
msgstr ""
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Running below line gives 3957 as length of longest line in file 20121119_SRMNotes_init.dat
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I am writing a bash script to find out all the files in a directory which are empty. I am running into multiple issues. I will really appreciate if someone can please help me.
#!/bin/bash
DATE=$(date +%m%d%y)
TIME=$(date +%H%M)
DIR="/home/statsetl/input/civil/test"
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Hello all,
I need to find the longest string in a select field and print that field.
I have tried a few different methods and I always end up one step from where I need to be.
Methods thus far:
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The above... (6 Replies)
Good Morning/Afternoon All,
I am using the nawk utility in korn shell to find the longest field and display that result.
My Data is as follows:
The cat ran
The elephant ran
Milly ran too
We all ran
I have tried nawk '{ if (length($1) > len) len=length($1); print $1}' filename
The... (5 Replies)
Hi Everyone,
I am trying to write a shell script that can find the longest phrase that appears at least twice in an online news article. The HTML has been parsed through an HTML parser, converted to XML and the article content extracted. I have put this article content in a text file to work... (24 Replies)
Dear All,
To find the length of the longest line from a file i have used wc -L which is giving the proper output...
But the problem is AIX os does not support wc -L command.
so is there any other way 2 to find out the length of the longest line using awk or sed ?
Regards,
Pankaj (1 Reply)
10-27-2010
