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Shell Programming and Scripting

Command That Gives Booting Times

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# 8  
Old 10-23-2010
Ah ha! Thank you for this unexpected enlightenment.

Then let me diverge from the problem statement to mention something I have done that provides similar information for my own use and amusement.

I wrote a bash script that cron runs every morning. Here is what it does:
  • Parse the output of uptime to see how many days the system has been running
  • Parse the last line of of my uptime log to see the last number of days logged
  • If today's uptime is longer than in the last line, delete the last line
  • Append a line with today's date and the number of days up
The result is a log file that lists how many days I had been running each time I shutdown or rebooted.

I didn't know about the last command. That's kind of interesting, though I'm not sure it will be of use to me.
# 9  
Old 10-23-2010
In the commercial world remember that "last" reads the "wtmp" file. This file is well known for growing rapidly so many administrators age the file say weekly and keep a couple of months worth.

A reliable unix system may be up for more than a year. Even if you don't age the "wtmp" file bear in mind that "who -b" doesn't say which year!
# 10  
Old 11-02-2010
solution
solution for this problem:

Code:
if [ -z "$1" ]   # if there is no input
then
    echo "enter the number of days"
exit 0
fi


touch rebootSwap.txt
last reboot > rebootSwap.txt
number=$1
for (( i=0; i<$number; i++ ));
do
tempDate=`date --date="$i days ago" '+%b %d'`     # makes the temp day i days ago  in %b %d format
CurrentCount=`grep -i "$tempDate" rebootSwap.txt | wc -l` # search the temp day in text
DATE=$(date -d "$tempDate" +"%d/%m/%y")          


echo "$DATE booted $CurrentCount times" # print the date and boot count
done
rm rebootSwap.txt

Last edited by radoulov; 11-02-2010 at 02:10 PM.. Reason: Code tags, please!
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