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Parsing the list in korn shell

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# 1  
Old 10-19-2010
Parsing the list in korn shell
Hi

I wanted to print/store just a specific element of the list . I have got the list as an output of grep command.

here is code snap below :

Code:
end_no=`egrep -ni '!return code: 0|return code other than 0' temp.log | cut -d':' -f1`

this will return the line numbers in end_no. I just wanted to know the 2nd positioned line numbers. please let me know the way to do .
Thanks:

Moderator's Comments:
Mod Comment Use [code] and [/code] tags when posting code, data or logs etc. to preserve formatting and enhance readability, thanks.
Last edited by zaxxon; 10-19-2010 at 07:11 AM..
# 2  
Old 10-19-2010
Use an array:
Code:
#!/usr/bin/ksh

set -A end_no

end_no="`egrep -ni '!return code: 0|return code other than 0' temp.log | cut -d':' -f1`"

echo ${end_no[2]}

exit 0

Not sure how the value/list of end_no looks alike but generally that should work.
# 3  
Old 10-19-2010
Thats is not working .. no output from echo stmt.

the list looks like this - 22 44 66:
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