unix korn shell leap years problem


 
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Old 10-19-2010
unix korn shell leap years problem

Write a function called dateToDays that takes three parameters -a month string such as Sep, a day number such as 18, and a year number such as 1962-and return s the number of days from January 1, 1900, to the date.
Notes: I am asking you to account for leap years.

my script is not working i need help
-----------------------------------------
Code:
dateToDays()
{
typeset total
 case $month in 
  "January") 
   month=1
   ;;
  "Febuary")
   month=2
   ;;
  "March")
   month=3
   ;;  
  "April")
   month=4
   ;;
  "May")
   month=5
   ;;
  "June")
   month=6
   ;;
  "July")
   month=7
   ;;
  "August")
   month=8
  ;;
  "September")
   month=9
   ;;
  "October")
   month=10
   ;;
  "November")
   month=11
   ;;
  "December")
  esc
 ((total=(month-1)*30+(day )+(1900-year)))
 return $total
}
# main program
echo enter month 
read month
echo enter day
read day
echo enter year
read year
dateToDays month day year
total = $?
echo the total days are $total


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Mod Comment Homework and coursework questions can only be posted in this forum under special homework rules.

Last edited by Scott; 10-19-2010 at 07:39 AM.. Reason: Homework. Closed.
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