changing YYYY-MM-DD to DDMMYY


 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting changing YYYY-MM-DD to DDMMYY
# 1  
Old 07-28-2004
changing YYYY-MM-DD to DDMMYY

Hi all

Wonder if you can help , I have a comma delimited file where the 13th to the 31st character of each line is populated by the date and time."2004-07-21 09:39:06"

16-5-141551,2004-07-21 09:39:06,8815
22-5-340394,2004-07-22 09:39:41,8001
22-5-340433,2004-07-23 09:42:20,1701

I have been asked to remove the time completely (i can probably work that bit out for myself) and reformat the date to DDMMYY so effectivly the file should look like this

16-5-141551,210704,8815
22-5-340394,220704,8001
22-5-340433,230704,1701

I really havent got a clue how to get started on this, hence the post, any help would be greatly appreciated

Gary
# 2  
Old 07-28-2004
Can you import the file into excel and then do a date conversion format on the cells the dates are in?
LordJezo
# 3  
Old 07-28-2004
Code:
#!/usr/local/bin/perl


sub parse_csv {
    my $text = shift;      # record containing comma-separated values
    my @new  = ();
    push(@new, $+) while $text =~ m{
        # the first part groups the phrase inside the quotes.
        # see explanation of this pattern in MRE
        "([^\"\\]*(?:\\.[^\"\\]*)*)",?
           |  ([^,]+),?
           | ,
       }gx;
       push(@new, undef) if substr($text, -1,1) eq ',';
       return @new;      # list of values that were comma-separated
}


open(FP,"<log.txt");
open(NF, ">out.txt");



while($line = <FP>){
	@fields = parse_csv($line);
	@fields[1] =~ /(\d\d\d\d)-(\d\d)-(\d\d)/;
	$y = $1;
	$d = $2;
	$m = $3;

	$y =~ /(\d)(\d)(\d)(\d)/;
	$t = $1;
	$h = $2;
	$n = $3;
	$o = $4;
	$out = "@fields[0],$m$d$n$o,@fields[2]\n";
	print $out;
	print NF $out;	
}

close FP;
close NF;



Have a nice Day Smilie
# 4  
Old 07-29-2004
Using awk...
Code:
awk '
  BEGIN {
    FS=OFS=","
  }
  {
    $2 = substr($2,9,2) substr($2,6,2) substr($2,3,2)
    print $0
  }
' infile > outfile

Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. UNIX for Beginners Questions & Answers

awk script to extract a column, replace one of the header and replace year(from ddmmyy to yyyy)

I have a csv which has lot of columns . I was looking for an awk script which would extract a column twice. for the first occurance the header and data needs to be intact but for the second occurance i want to replace the header name since it a duplicate and extract year value which is in ddmmyy... (10 Replies)
Discussion started by: Kunalcurious
10 Replies

2. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file... (3 Replies)
Discussion started by: Roozo
3 Replies

3. UNIX for Dummies Questions & Answers

Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know... (4 Replies)
Discussion started by: newbie2010
4 Replies

4. Shell Programming and Scripting

Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

Hi I have a problem with Date format in my code. 1st I am trying to convert today's date to yesterday's using YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'` And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
Discussion started by: nithinankam
3 Replies

5. Shell Programming and Scripting

Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ... (4 Replies)
Discussion started by: Adamm
4 Replies

6. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

7. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

Hi all I have some pipe-separated data in the form: 5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF 12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF 1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE I need to zero-pad the single-digit days and months, using... (3 Replies)
Discussion started by: jgrogan
3 Replies

8. Shell Programming and Scripting

Convert DD-MMM-YYYY to MM-DD-YYYY

I have a file which has 100k+ records like this abc,05-JUN-1974,def,lkj,aaa def,11-SEP-1975,ghj,dis,dea I want to convert ex 05-JUN-1974 to 06/05/1974 Please help me with awk script to convert the whole file into MM-DD-YYYY Thank you! (2 Replies)
Discussion started by: nuthalapati
2 Replies

9. Shell Programming and Scripting

converting the date field from dd/mm/yyyy to yyyy/mm/dd

How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix my script will generate text file which have two fields one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Discussion started by: pareshan
4 Replies

10. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Discussion started by: stringzz
9 Replies
Login or Register to Ask a Question