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Print lines where variables occur more than once using grep

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# 1  
Old 10-18-2010
Print lines where variables occur more than once using grep
Hello,
I want to only print lines where variables occur more than once using grep.

For eg:

Input:
Code:
$this is a comment
int a,b,c,b;
int b,c;
int d,e;
int f,g,f;
x=y+5;

For the above input, the output would be
Code:
int a,b,c,b;
int f,g,f;


I have done grep '^[ ]*int[ ]*\([a-z][a-z0-9]*,\?\)\{1,\};$' to match all the declaration statements, and print all of them. But I am not able to print only those where a variable occurs more than once. I know I've to tweak my regex a bit, but I've tried most options!

Thanks for any help.


Thanks,
Prasanna
Last edited by Scott; 10-18-2010 at 04:56 AM.. Reason: Code tags, please...
# 2  
Old 10-18-2010
hmm.

tweaking your regex to

Code:
#  grep '^[ ]*int[ ]*\([a-z][a-z0-9]*\).*\1' infile 
int f,g,f;

will match where any single char further down the line matches the first char after "int "

I find it easier to think in awk:

Code:
nawk -F"[ \;]" '
/^int/{f=0;n=split($2,a,",")
  for (x=1;x<n;x++) {
    for (y=x+1;y<=n;y++){
      if (a[x]==a[y]){f=1}
    }
  }
if (f==1) {print}}' infile 

int a,b,c,b;
int f,g,f;

HTH
# 3  
Old 10-18-2010
Thanks a lot for your reply.

Yes, I got to that too. But I would want to match any variable(not only the first), if it occurs more than once.

Thanks,
Prasanna
# 4  
Old 10-18-2010
Code:
$ sed '/\<int\>.*\<\([a-zA-Z0-9_]\{1,33\}\)\>.*\<\1\>/!d' <<!
\$this is a comment
int a,b,c,b;
int b,c;
int d,e;
int f,g,f;
x=y+5;
!
int a,b,c,b;
int f,g,f;
$

Narrative: Find lines with the word int followed somewhere by a variable name word followed somewhere by the same variable name. The \< and \> like ^ and $ must be outside the \(\). The \< and \> work in sed but not always in grep, and stop working with later regex libs, and they become \b.

Regex Tutorial - \b Word Boundaries
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