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How to extract url from html page?

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Top Forums Shell Programming and Scripting How to extract url from html page?
# 8  
Old 10-16-2010
Oops...
Code:
awk '/^id/{print $2}/^href/{printf $2 RS}' FS='"' RS=" " infile

# 9  
Old 10-16-2010
Quote:
Originally Posted by Scrutinizer
Oops...
Code:
awk '/^id/{print $2}/^href/{printf $2 RS}' FS='"' RS=" " infile

Code:
<a href="http://awebsite"  id="awebsite" class="first" someattribute="last" > website</a>
<a href="http://bwebsite"  id="bwebsite" class="first">websiteb</a>

Nice one but I guess the OP needs the one which is in red only, not $2 after id.

---------- Post updated at 12:53 PM ---------- Previous update was at 12:45 PM ----------
Quote:
Originally Posted by kurumi
Code:
$ cat file
<a href="http://awebsite"  id="awebsite" class="first" someattribute="last" > website</a>
<a href="http://bwebsite"  id="bwebsite" class="first">websiteb</a>
 
$ awk -F'href="|"  |">|</' '{for(i=2;i<=NF;i=i+4) print $i,$(i+2)}' file
http://awebsite a>
http://bwebsite websiteb
 
$ ruby test.rb
-->http://awebsite,  website
-->http://bwebsite, websiteb

I guess no space before and after >(on red below) in the original requirement from the OP so it will work fine as below if you remove the space
Code:
 
$ cat file
<a href="http://awebsite"  id="awebsite" class="first" someattribute="last" > website</a>
<a href="http://bwebsite"  id="bwebsite" class="first">websiteb</a>
 
$ awk -F'href="|"  |">|</' '{for(i=2;i<=NF;i=i+4) print $i,$(i+2)}' file
http://awebsite  website
http://bwebsite websiteb

# 10  
Old 10-16-2010
Quote:
Originally Posted by malcomex999
I guess no space before and after >(on red below) in the original requirement from the OP so it will work fine as below if you remove the space
HTML is not regular. you won't know in future there will be more or less spaces as web page changes. Ideally, we should use a parser.
# 11  
Old 10-16-2010
Wow I am really having trouble reading today... This then maybe?
Code:
awk '$2=="a href="{printf $3; getline; print OFS $1}' RS='>' FS='["<]'

# 12  
Old 10-16-2010
Quote:
Originally Posted by Scrutinizer
Code:
awk '$2=="a href="{printf $3; getline; print OFS $1}' RS='>' FS='["<]'

Nice. works with OP's mini sample. But I used it to parse a page like that of Google, for exampl, i hit error.
Code:
awk: (FILENAME=file FNR=239) fatal: not enough arguments to satisfy format string

# 13  
Old 10-16-2010
OK Smilie , the next attempt then:
Code:
awk -F'>' '/^a href/{split($1,F,"\"");print F[2],$NF}' RS='<'

# 14  
Old 10-16-2010
Quote:
Originally Posted by Scrutinizer
Code:
awk -F'>' '/^a href/{split($1,F,"\"");print F[2],$NF}' RS='<'

Nice. It worked. Now, how about taking care of HTML entities like ▼ ?
This is a symbol (down arrow). Gawk doesn't return it. But my parser does. Any ways to set it with gawk?
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