Shell Programming and Scripting

I am trying to execute the following command to check the existance of a file (which has a date timestamp on it). If there are more than one file, then also it should give me 'success' result.

Code:

if [ -e /path/filename1.* ]
then
        <do some work> 
else
        <no files>
fi

Since there are more than one file...the above command throws an error.

Can someone please help?

Thanks

Try this:

Code:

exists()
{ 
  [ -e "$1" ]
}

if exists /path/filename.* 
then
        <do some work> 
else
        <no files>
fi

What Operating System?
What Shell?
What is the error message?
Do any of the filenames contain a space character?

Could try..

Code:

for i in `ls /path/filename.*`
do
	if [ -e $i ]
	then
		echo "File Exists"
	else
		echo "Fail"
	fi
done

@Scrutinizer

Is: `ls /path/filename.*` really needed here?

Why don't you use just:

Code:

for i in /path/filename.*
do
	if [ -e $i ]
	then
		echo "File Exists"
	else
		echo "Fail"
	fi
done

Check this link: Useless Use of Cat Award

That's Unix..Thank you and noted!

Guys - I am looking for a one line command, if possible please

What Operating System? - Linux
What Shell? - ksh
Do any of the filenames contain a space character? - No, its only alphabets and numbers

What is the error message? -
script.ksh[3]: [: /path/filename1.20100930_18_18_40.tar.gz: unexpected operator/operand

Please note I am searching in a directory where it has many files with different time stamps

for ex:
filename1.20101004_18_18_40.tar.gz
filename1.20101001_18_18_40.tar.gz
filename2.20100918_18_18_40.tar.gz
filename2.20100906_18_18_40.tar.gz
filename1.20101002_18_18_40.tar.gz

So I just want to check the existance of any of the file starting with filename1

filename1.*

Hope this makes sense...