Thanks for the help.
i changed the code accordingly.
but i am facing the below error message.
Code:
>./ora_error.sh
./ora_error.sh[6]: cd: bad argument count
grep: can't open THerrFile_2.err
grep: can't open THerrFile_3.err
grep: can't open THerrFile_4.err
grep: can't open THerrFile_5.err
Last edited by Scott; 10-12-2010 at 09:23 AM..
Reason: Code tags
1.The value of the variable a holds something like
Quote:
-rw-r--r-- 1 ondesk staging 155 Oct 8 03:17 some.txt
. So when u try to change directory (cd $a) the shell will be unable to do so and throws the above error.Hence try to give the correct directory name to cd
2.Also make sure the argument to cd is given as absolute path (if changing to different directory)
Quote:
grep: can't open THerrFile_2.err
Make sure above such file exist in the current working dir. i.e where you have saved/run this shell script.Else specify the correct path.
drwxrwsr-x 2 tia uniqgrp 12288 10 Oct 00:30 CSB.Oct10_00:01/
i need to get only the directory name i.e CSB.Oct10_00:01 part but not the entire line.
please advice.
---------- Post updated at 09:55 AM ---------- Previous update was at 08:38 AM ----------
Hi,
Code:
#catr.ksh
#!/bin/ksh
v=""
a='ls -ltrd CSB.*|tail -1|egrep -v '^CSB.*'|awk '{ print$9 }''
cd $a
rm oraerr_output.txt
for j in 1 2 3 4 5
do
v="THerrFile_$j.err";
grep -i "$j:Error" $v >>oraerr_output$j.txt
cat oraerr_output$j.txt >> oraerr_output.txt
rm oraerr_output$j.txt
done
in the above code for variable a i am getting a directory name.
but in "Cd $a" it is not going into the directory.
because i am getting the below errors.
}
grep: can't open THerrFile_1.err
grep: can't open THerrFile_2.err
grep: can't open THerrFile_3.err
grep: can't open THerrFile_4.err
grep: can't open THerrFile_5.err
Please advice if the above code is correct or i am going wrong some where.
2. Before grep'ing the file THerrFile_*.err take sometime to check if that file exist in your current working dir or where this script is stored.As the error states
Quote:
grep: can't open THerrFile_1.err
- there is no such file in the current dir.
This User Gave Thanks to michaelrozar17 For This Post:
once the cd command is executed then i can grep the files in the directory.As the directory is not changing i am not able to grep and it says can't open the THerrFile_2.err file.
the value of a will be like CSB.Oct11_17:30.
it is not working .
please help.
-------
It is working fine now.
I am copying the final code.hope it may help some one.
Code:
#catr.ksh
#!/bin/ksh
v=""
a=$(ls -ltrd CSB.*|tail -1|egrep -v '^CSB.*'|awk '{ print$9 }')
cd $a
rm oraerr_output.txt
for j in 1 2 3 4 5
do
v="THerrFile_$j.err";
grep -i "$j:Error" $v >>oraerr_output$j.txt
cat oraerr_output$j.txt >> oraerr_output.txt
rm oraerr_output$j.txt
done
the code that i pasted in my previous posts works fine ,if all files are existing.if any file is missing it is comming out.
but my requirement is,it should go to next file and grep the ora-messages.
i am copying my code also.
for example if we couldn't find THerrFile_1.err file in the directory.it is comming out,it should go to
THerrFile_2.err ,THerrFile_3.err ,THerrFile_4.err ,THerrFile_5.err files and pick the ora-messages.
please advice.
Code:
#catr.ksh
#!/bin/ksh
v=""
a=$(ls -ltrd CSB.*|tail -1|egrep -v '^CSB.*'|awk '{ print$9 }')
cd $a
rm oraerr_output.txt
for j in 1 2 3 4 5
do
v="THerrFile_$j.err";
grep -i "$j:Error" $v >>oraerr_output$j.txt
cat oraerr_output$j.txt >> oraerr_output.txt
rm oraerr_output$j.txt
done
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10-12-2010
