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How to generate 10.000 unique numbers?

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Top Forums Shell Programming and Scripting How to generate 10.000 unique numbers?
# 8  
Old 10-01-2010
Quote:
Originally Posted by xrays
... they should be more complex. with 12 to 18 chars. and more random.
Here's a short Perl script that generates 10 distinct random numbers between NUM1 = 999,999,999,999 (12 digits) and NUM2=999,999,999,999,999,999 (18 digits). $range in the script is NUM2 - NUM1.

Code:
$
$ perl -e 'BEGIN {$min=999_999_999_999; $range=999_999_000_000_000_000; $n=0; $total=10}
           do { $x=sprintf("%18.0f\n",int(rand($range))+$min);
                if (not defined $rnd{$x}) {$rnd{$x}++; print $x; ++$n}
              } until ($n == $total)'
435059158691406270
823944267852783230
160920028533935550
857452535125732480
490753683074951170
386475222900390660
919342121673584000
339935962799072260
483002225982665980
952148485351562500
$
$ perl -e 'BEGIN {$min=999_999_999_999; $range=999_999_000_000_000_000; $n=0; $total=10}
           do { $x=sprintf("%18.0f\n",int(rand($range))+$min);
                if (not defined $rnd{$x}) {$rnd{$x}++; print $x; ++$n}
              } until ($n == $total)'
775116191680908160
462250293609619140
214142631561279300
963470495513916030
866027966003417980
710083297729492220
 12421641876220704
632690796997070340
597626134796142590
502472421356201150
$
$ perl -e 'BEGIN {$min=999_999_999_999; $range=999_999_000_000_000_000; $n=0; $total=10}
           do { $x=sprintf("%18.0f\n",int(rand($range))+$min);
                if (not defined $rnd{$x}) {$rnd{$x}++; print $x; ++$n}
              } until ($n == $total)'
868713510192871040
987182630004882820
978912374603271420
379791879974365250
296448457458496060
946075493377685500
 26398678680419920
513519773590087870
920135577911376900
439606273284912130
$

tyler_durden
This User Gave Thanks to durden_tyler For This Post:
xrays
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