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How to check a list of 4-5 strings in IF condition?

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# 1  
Old 09-29-2010
How to check a list of 4-5 strings in IF condition?
Hi Unix Champs,

I am a newbe to UNIX.

I need to create a condition where I want to check the value of a variable with 5 different strings, if matched then exit 1.

For ex:
Code:
if [[ $var=one or $var=two or $var=three or $var=four or $var=five ]]
then
       echo "yes, condition satisfied...."
else  
       echo "no, condition not satisfied..."
fi


Regards,
A beginner...

Moderator's Comments:
Mod Comment With so many posts you should be familiar using code tags. Use them in future please, ty.
# 2  
Old 09-29-2010
Code:
if [[ $var = "one" || $var = "two" || $var = "three" || $var = "four" || $var = "five" ]]
then
       echo "yes, condition satisfied...."
else  
       echo "no, condition not satisfied..."
fi

Last edited by zaxxon; 09-29-2010 at 11:37 AM.. Reason: added quotation marks.. and blanks between operators
# 3  
Old 09-29-2010
Hi....Thanks for the reply....
I tried with the code you suggested, but getting following error.....

ksh: 0403-057 Syntax error: `|' is not expected.
# 4  
Old 09-29-2010
Forgot to add double quotation marks when testing a string. Have been added in the post above. Oh and blanks between operators!
# 5  
Old 09-29-2010
still getting the same error.....checked with quotation marks for all 5 strings...
# 6  
Old 09-29-2010
use case and esac

Code:
case "$var" in
  one|two|three|four|five ) echo "yes";;
  *) echo "no";;
esac

# 7  
Old 09-29-2010
I was still editing, check my post. There are missing blanks between the operators and the " = ".
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