Shell Programming and Scripting

I've got an assignment where I've made a script that searched and found files that meet certain requirement. (Files that are a size that is from "x" to "y" in size and has a certain name).

The script sends the output to a file that gathers the info.

The problem is I'd like to sort what's displayed in that file by size (and I need info on how large the files are, filename and directory).

I've read on the forums and found cases that are ALMOST right on, 'cept I can't use any "ls" commands because that would list and sort all the files in a directory, not the results that I get from my script.

This is the script:

Code:

#!/bin/bash
find . -name 'test*' -size +32c | sort > findtest_info.txt

It returns:

./test2.sh
./test53.sh
./test.sh
./test.txt

Is there any way to sort it via filesize and display the size of the files. In ascending order?

Complete noob here, just started with bash - Cheers, BobbyTee.

Try this

This will get the size of the files in KBs and will sort in ascending order of size with filename printed, example

8 ./vishu2
80 ./vishal
112 ./vishal_log_bak

For me this returns the correct files, but it says that they're all 4kb.. :S
4 ./test2.sh
4 ./test53.sh
4 ./test.sh
4 ./test.txt

The files range from 34bytes to 1.7kb.
Cheers, BobbyTee

God dag til Norge.

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