Shell Programming and Scripting

I apologize if this topic has been beaten to death here, but my limited searching skills did not throw up any results.

Here's what I am trying to accomplish
List all the files in a certain directory; assign the file names to an array which will be used later in the script.
My script looks like this

Code:

cd /tmp/tempDir

filelist=`ls -l | awk '{print $9}'`

numFiles=#logic for finding number of files#
i=1
while [ $i -le $numFiles ]; do
        filearray[$i]=`echo $filelist | awk '{print $i}'`
        echo ${filearray[$i]}
        i=`expr $1 + 1`
done

For reasons beyond my understanding, the awk command within the loop does not seem to get the value of 'i'.

am I missing something?

Appreciate your help in advance.

Vinay

P.S. I am working on Solaris, if it helps.

Try something like this:

Code:

cd /tmp/tempDir

i=1
for file in *
do
  filearray[$i]="$file"
  echo ${filearray[$i]}
  i=$(( $i + 1 ))
done

Appreciate the quick response. It worked!