Shell Programming and Scripting

Hi All,

I have a file containg lines along the likes of:

Code:

18:02:00 JOB02084722
18:09:00 2010120942
18:12:04 JOB02084723
18:34:16 20100709

etc.

What I want to do is remove the entire line when field 2 starts with a number so I'm left with:

Code:

18:02:00 JOB02084722
18:12:04 JOB02084723

I can't use awk to remove all numberics because they appear validly in some of the jobnames. I've had a look through a lot of awk and sed stuff but can't seem to find it. Any help much appreciated.

G

Something like:

Code:

awk '$2 !~ /^[0-9]/'

Code:

$ ruby -ane 'print if $F[1]!~/^\d/' file
18:02:00 JOB02084722
18:12:04 JOB02084723

Thanks for that it works fine but I forgot to add that sometimes the file contains a blank record in field 2.

Could you help with the awk for removing ALL non-aplha characters?

Code:

sed '/ [0-9]/d' infile

Your question isn't clear.

Define a "blank record". Does that mean "no record"? "remove all non-alpha characters" from where?

This wouldn't work if there is no second record, if the second record has any numbers or if there are more than two records.

Cheers Scottn. The file looks like:

Code:

18:02:00 JOB02084722
18:06:00
18:09:00 2010120942
18:12:04 JOB02084723
18:34:16 20100709

Basically all I want from it are the lines where the 2nd field starts with 'JOB'. All other lines can be deleted. Appreciate your help