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use input filename as an argument to name output file

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# 1  
Old 09-26-2010
use input filename as an argument to name output file
I know this is a simple matter, but I'm new to this.

I have a shell script that calls a sed script from within it. I want the output of the shell script to be based on the input file I pass as an argument to the original script. In other words...

Code:
./script.sh file.txt

(script.sh calls sed script, creates file.txt.out)

Code:
more file.txt.out
Results!

What do I need to put in the line that calls the sed script? I have the impression is should be something like...

Code:
./sedscript.sed $1 > $1.out

# 2  
Old 09-26-2010
looks good to me - does this not work ?
# 3  
Old 09-26-2010
Sure enough, it did! I wasn't posting from the same computer where I was working on the script, and it didn't seem possible it could be that simple.

Thanks!

---------- Post updated at 06:20 PM ---------- Previous update was at 06:20 PM ----------

Sure enough, it did! I wasn't posting from the same computer where I was working on the script, and it didn't seem possible it could be that simple.

Thanks!
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