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Shell Programming and Scripting

Pass command line argument to variable

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# 8  
Old 09-27-2010
Second cut delimiter column # is wrongly put as 5 instead of 2.

Code:
get_input_file()
{
FILE=$1
echo $FILE
TYPE=`echo $FILE | cut -d "_" -f 3`
echo "Type is $TYPE"
EXTN=`echo $FILE | cut -d "." -f 2`
echo "Extension is $EXTN"
}

### Function Call
get_input_file MigBIOS_CR_GLOBAL_20100924021422.CSV

Output
Code:
$ sh script.sh
MigBIOS_CR_GLOBAL_20100924021422.CSV
Type is GLOBAL
Extension is CSV

# 9  
Old 09-28-2010
Thanks a lot Kmuthu_gct.

Now I am able to print values of TYPE and EXTN.

but still I am getting errors for input file data as,
Sample.ksh[97]: abcdefghij: not found.
Sample.ksh[97]: 20100903040607: not found.
Sample.ksh[97]: 1234567891: not found.
Sample.ksh[97]: GLOBAL: not found.

Could you please help me out.
Last edited by Poonamol; 09-28-2010 at 12:30 AM..
# 10  
Old 09-28-2010
Bug
Hi Poonamol

Just comment/remove this line in your code where you are checking for file.

Code:
 
#. $1

# 11  
Old 09-28-2010
Thanks a lot Smilie
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