Shell Programming and Scripting

use Perl to get the paragraph which contains the word "Waiting" ...

Code:

perl -00 -wne 'print if /Waiting/' infile.txt

I would do that, yes, if q proc produces output like you described above...

Code:

awk '/^Process /{x=(x)?x FS$0:$0}/Waiting/{print x}!NF{x=z}' infile

Try:

Code:

awk '/Waiting/{print $3}' RS= file

Hehehe Franklin52, of course

Look nice but what about the OP requirement?

AH! now this "almost" works...

If i use my test file it works, but when i plug this into my "q proc" query, i only get the second line returned... (Process Description).

What i noticed though, is that my test file (test.out) contains the same data but all 3 lines (Procress Number, Description and Status) start at character 0. Meaning on the far left side. but if i issue a "q proc" to test it in my real environment, the Process Number starts indented about 5 characters compared to the Process Description...

Kinda like this:

q proc | awk '/^Process /{x=(x)?x FS$0:$0}/Waiting/{print x}!NF{x=z}'

^^Process Number: 23823
Process Description: Space Reclamation
^^^^^^^^Status: blahblahblah
(^^^ are actually spaces...can't seem to get this post to insert spacing at the beginning...)

I get this in return:

Process Description: Space Reclamation

Could it be because that first line is indented?

---------- Post updated at 03:41 PM ---------- Previous update was at 03:33 PM ----------

Actually, forget about that...it is the "^" within the awk '/^Process right? If i remove it, it works...

Thanks