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Search file for pattern2 starting from occurence of pattern1

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# 1  
Old 09-22-2010
Search file for pattern2 starting from occurence of pattern1
Hi folks,

I have a file which contains several occurences of 2 different patterns. I need to find out the line of first occurence of pattern2 starting after the position of first occurence of pattern1.

example file:
Code:
aaaa
pattern2
bbbb
pattern1
ccc
pattern2
ddd
pattern1
eee
pattern2
fff
....

Desired output is 6 - line number of first occurence of pattern2 after the first occurence of pattern1
I intended to use grep with -m option. In the manual page there is mentioned: ...
Quote:
-m NUM, --max-count=NUM
Stop reading a file after NUM matching lines. If the input is standard input from a regular file, and NUM matching lines are
output, grep ensures that the standard input is positioned to just after the last matching line before exiting, regardless of
the presence of trailing context lines. This enables a calling process to resume a search.
... but I don't know how to resume search with pattern2 after using command
Code:
grep -m 1 pattern1 filename

Please help.
Last edited by Franklin52; 09-22-2010 at 10:41 AM.. Reason: Please use code tags, looks much better, no?
# 2  
Old 09-22-2010
Code:
# awk 'x&&/pattern/{print NR,$0;exit}/ccc/{x=1}' file
6 pattern2



---------- Post updated at 09:36 AM ---------- Previous update was at 09:35 AM ----------

Admin & Moderators , please remove my duplicate post.

Thanks,
# 3  
Old 09-22-2010
Sorry, I don't understand. Can you explain a little your script please?
But I am afraid if it works .... in the given example the strings aaa, bbb, ccc ... must be considered only as dummy strings and in reality they can be replaced by any string/lines.
# 4  
Old 09-22-2010
Code:
# cat f5
aaaa
pattern2
bbbb
pattern1
ccc
pattern2
ddd
pattern1
eee
pattern2
fff
# awk '
     x &&/ pattern/{print NR,$0;exit}    # Step 2: If variable x has a value and second pattern match record print record(line) number (NR), record and exit.
     /ccc/{x=1}                          # Step 1: On first occurrence of pattern1(ccc in you example) set value of variable x to 1
' file
6 pattern2

This User Gave Thanks to danmero For This Post:
sameucho
# 5  
Old 09-23-2010
Thank you for your help and explanation.
This slight modification of your script fulfil my needs:

Code:
awk 'x&&/pattern2/{print NR,$0;exit}/pattern1/{x=1}' file

But after all to learn more, is there any solution with -m option using grep?
# 6  
Old 09-23-2010
MySQL
actually `grep -m` does not provide your req as exactly
beacuse -m parameter gives th result your pattern at how many number in max

but i try also Smilie
Code:
# grep -nA 10 pattern1 file | grep -w -m1 pattern2
6-pattern2

and can try powerfull sed Smilie
Code:
# sed '=' file | sed -e N -e 's/\(.*\)\n\(.*\)/\1 \2/' | sed -e '/1/,/pattern1/d' -ne '/pattern2/p'
6 pattern2

This User Gave Thanks to ygemici For This Post:
sameucho
# 7  
Old 09-23-2010
Hi ygemici,
thanx for your posts, but your solution with grep is not universal as limited by -A option.

sed is fine, but proposed awk script is more comprehensible in this case.
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