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Using sed w/variables containing "\"

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# 1  
Old 07-06-2004
Using sed w/variables containing "\"
I'm trying to perform a search and replace on a variable that could potentially contain a \. For example:

#!/bin/ksh

VAR1=$1

VAR2=`printf "$VAR1\n" | sed 's/\\\/--REPLACED--/g'`

The problem I am running into is the printf is treating the \ as an escape to the character following it and not as a literal \. I do not have the option to change the input to the script (to \\). Any ideas?

Thanks,
Joel
# 2  
Old 07-06-2004
You can try this:

Code:
printf '%s\n' "hi there"
printf '%s\n' $VAR

to "hide" that backslash
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