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Simple script to count files

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# 1  
Old 09-17-2010
Simple script to count files
Hello,
I am new to shell scripting and I need your help.
I have found similar scripts in the forum but I need further assistance.

I am building a script to use hourly in cron to mailx me if the number of files in a path is less than e.g 100

I have started with the following:

Code:
#!/bin/sh
ymdh=`${LIB}/YYYYMMDDHH24-2`    <-GATHERED FROM ORACLE SCRIPT
while true ; do
cd /Data/ftpdir
files_count =`$ll *${ymdh}* |wc -l`
if [ ${files_count} < 100 ]
then

      mailx "No_of_files_2 _hrs_before" ............................
fi
done


Any help will be much appreciated.
Last edited by Scott; 09-17-2010 at 08:09 AM.. Reason: Please use code tags
# 2  
Old 09-17-2010
Hi, as you will have a cron job that will run hourly, you don't really need the "while true" part.

The script is:
Code:
#!/bin/sh
checkPath="<PathToCheck>"
minNumberOfFiles=100
numOfFiles=`ls -l "${checkPath}" | egrep '^-r' | wc -l`

if [ ${numOfFiles} -lt ${minNumberOfFiles} ]
then
echo "Number Of Files In: [${checkPath}] Less Than ${minNumberOfFiles}: [${numOfFiles}]" | mailx -s "Num Of Files" you@example.com
fi

Of course, there are other ways to do it! You can change numOfFiles to:
Code:
numOfFiles=`find ${checkPath} -type f -maxdepth 1 | wc -l`

This User Gave Thanks to felipe.vinturin For This Post:
drbiloukos
# 3  
Old 09-17-2010
Thank you !
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