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-exec cmd in ksh script

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Top Forums Shell Programming and Scripting -exec cmd in ksh script
# 8  
Old 09-16-2010
I see - but is there no way to do this without requiring the double quotes around the parameter passed to the script?

I can see people often forgetting to double-quote their parameter, with possibly terrible results!
# 9  
Old 09-16-2010
File name expansion is a shell feature that can be disabled with "set -f" in the user's shell but that would probably lead to more confusion.
# 10  
Old 09-16-2010
Perhaps I should first verify that the parameters are each quoted before I execute the find cmd - if they are not, I could terminate the script with an error message.

So I'd need to look for matching pairs of double-quotes. I should be able to do that fairly easily, I think.
# 11  
Old 09-17-2010
Quote:
Originally Posted by Tanuka
Perhaps I should first verify that the parameters are each quoted before I execute the find cmd - if they are not, I could terminate the script with an error message.

So I'd need to look for matching pairs of double-quotes. I should be able to do that fairly easily, I think.
That won't work. The quotes are removed by the shell before passing the parameters to the called program.
However, checking the arguments count should work as a workaround. If larger than the one expected, that would mean expansion had happen.
# 12  
Old 09-17-2010
Quote:
Originally Posted by jlliagre
That should be:

Code:
./cpmany . "f*" /joe/stuff/

Just one more comment on that, it happens because the shell is expanding the wildcard: "*" before starting the script.

Check below:
Code:
####################################
# Example files
####################################
# ls -1 f*
file1
file2
file3
file4
file5
####################################

####################################
# Example script
####################################
# cat myScript.sh
#!/bin/bash

argCount=1

for scriptArg in "$@"
do
        echo "Arg#: [${argCount}] - Value: [${scriptArg}]"
        argCount=`expr ${argCount} + 1`
done
echo "Find Result"
find $1 -maxdepth 1 -type f -name "$2"
####################################

####################################
# Exemple execution - No double quotes
####################################
# ./myScript.sh . f*
Arg#: [1] - Value: [.]
Arg#: [2] - Value: [file1]
Arg#: [3] - Value: [file2]
Arg#: [4] - Value: [file3]
Arg#: [5] - Value: [file4]
Arg#: [6] - Value: [file5]
Find Result
./file1
####################################

####################################
# Exemple execution - Double quotes
####################################
# ./myScript.sh . "f*"
Arg#: [1] - Value: [.]
Arg#: [2] - Value: [f*]
Find Result
./file2
./file1
./file4
./file5
./file3
####################################

I hope it helps!

Regards.
# 13  
Old 09-17-2010
Quote:
Originally Posted by felipe.vinturin
Just one more comment on that, it happens because the shell is expanding the wildcard: "*" before starting the script.
Indeed. I wrote how this expansion can be disabled in post #9 https://www.unix.com/302453896-post9.html
# 14  
Old 09-17-2010
Quote:
Originally Posted by jlliagre
Indeed. I wrote how this expansion can be disabled in post #9 https://www.unix.com/302453896-post9.html
Sorry, I didn't see that!
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