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Need perl regular expression to remove the comment

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# 1  
Old 09-15-2010
Error Need perl regular expression to remove the comment
I need a perl substitution to remove only the comment in the line . That line may have '#' with in double quotes .I used the following ,

Code:
 s/(^.*\".+?#.+?\".+?)(#.*)/$1/g

It works for ,

Code:
print " not a comment # not a comment " . "not a comment # not a comment" ;  # It is a comment

but for the line like ,

Code:
print " not a comment # not a comment " . "not a comment # not a comment" ;

It gave the output ,

Code:
print " not a comment # not a comment " . "not a comment

It removes the text from the last '#' . Can any one give me the exact regular expression to solve this problem .

Thanks in advance .
# 2  
Old 09-15-2010
can you please add the output for first line for which code is working and the expected output of the second line.
# 3  
Old 09-15-2010
perl may help you
Code:
while(<DATA>){
  s/#(?=[^"]*$).*$//;
  print;
}
__DATA__
" not a comment # not a comment " . "not a comment # not a comment"
" not a comment # not a comment " . "not a comment # not a comment" ;  # It is a comment

# 4  
Old 09-16-2010
Code:
 ruby -ne 'print if gsub(/;.*#.*/,";")' file

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