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Substring using cut/awk/sed

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# 8  
Old 09-09-2010
Hi ,Thanks again... I have never used sed this way before , can u explain me the use of "...\" , ".*" & "n\" ?or direct me to a some page which will explain this usage ?
# 9  
Old 09-09-2010
3 usefull links about sed:
- sed - Wikipedia, the free encyclopedia
- sed_tutorial
- Using sed
This User Gave Thanks to felipe.vinturin For This Post:
sumoka
# 10  
Old 09-13-2010
Hi Scrutinizer/felipe ,

I have been going through teh tutorials & they are very helpful thansk a lot!

However , I tried two slightly different statements on the same string & the o/p varied drastically , it is due to the position of "." in the statement .

e.x.1
Code:
echo "ABCDEFGHIJ20100909.txt" | sed -n -e 's/\(..\)\(...\).*\([0-9]\{8\}\).*/\1,\2,\3,&/p'

o/p : AB,CDE,20100909,ABCDEFGHIJ20100909.txt --> as desired

e.x.2
Code:
echo "ABCDEFGHIJ20100909.txt" | sed -n -e 's/\(..\)\(...\)*\([0-9]\{8\}\).*/\1,\2,\3,&/p'

o/p : ABCD,HIJ,20100909,CDEFGHIJ20100909.txt


Can anybody explain how the position of "." dot affects the result ?
thanks in advance .

Moderator's Comments:
Mod Comment Please use code tags!
Last edited by Scott; 09-13-2010 at 04:38 AM.. Reason: fuhgot teh question...
# 11  
Old 09-13-2010
The differente between the dot(.) and the asterisk(*) are the following:
Code:
. Matches any single character
(character)*match arbitrarily many occurences of (character)

Which means that the ()* matches "arbitrarily many occurences" and that's why the difference between the two results.
# 12  
Old 09-13-2010
-Post deleted-
# 13  
Old 09-13-2010
in above code its searching date patter from right to left ,but if i wana to search from left to right ?

please suggest i have tried but unable to do
# 14  
Old 09-14-2010
Like this you mean?
Code:
$ echo XXXXXXXX20100909XXXXXXXXJIHGEFDABC.txt|sed 's/.*\([0-9]\{8\}\).*\(..\).\(...\).txt$/\3,\2,\1,&/'
ABC,EF,20100909,XXXXXXXX20100909XXXXXXXXJIHGEFDABC.txt
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