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wildcard in bash shell script

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# 8  
Old 09-08-2010
Like Corona688 says, it might be that you are listing the content of directories, try:
Code:
ls -d ./*

and see if that makes a difference
# 9  
Old 09-08-2010
This is not a problem in my case, since all files in my current directory do not have a name starting with ".".

Quote:
Originally Posted by methyl
If the only files in the directory have names starting with "." (like ".profile) they will not match "*".

To see them:

Code:
ls ./.??*



---------- Post updated at 10:00 AM ---------- Previous update was at 09:55 AM ----------

thanks for suggestion. I tried, and when I run the script, it gave the same error message:
ls: ./*: No such file or directory.

It looks like the script can not expand '*'. I just can not understand why.

Quote:
Originally Posted by Scrutinizer
Like Corona688 says, it might be that you are listing the content of directories, try:
Code:
ls -d ./*

and see if that makes a difference
# 10  
Old 09-08-2010
It's staring me in the face.

You are starting bash with the "-f" switch set. This turns off the filename generation features of bash. In other words it stops the "*" working.

Lose the "-f" .
This User Gave Thanks to methyl For This Post:
Corona688
# 11  
Old 09-08-2010
thanks a lot! It works when I drop off '-f'.

One more question: why does it work when I use '-f' in c shell?

Quote:
Originally Posted by methyl
It's staring me in the face.

You are starting bash with the "-f" switch set. This turns off the filename generation features of bash. In other words it stops the "*" working.

Lose the "-f" .
# 12  
Old 09-08-2010
"-f" has a different meaning in csh
Code:
$ man csh | grep -A1 '[[:space:]]\-f'
     -f     The shell will start faster, because it will neither search for nor execute commands from the file .cshrc in the
            invoker's home directory.  Note: if the environment variable HOME is not set, fast startup is the default.

This User Gave Thanks to Scrutinizer For This Post:
aerosols
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