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Use awk to print first 6 characters

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# 1  
Old 09-06-2010
Use awk to print first 6 characters
Hi,
i want to use awk to print the first 6 characters of a variable

Code:
awk -F"|" '$3>0 { print $3 }' z00.unl > z001.unl

but $3= 7 digits
and i just want to print the first 6 digits.

eg 1005779 but i want to print only 100577
Last edited by Scott; 09-06-2010 at 08:10 AM.. Reason: Please use code tags
# 2  
Old 09-06-2010
Code:
$ cat file1
abc|ABC|123456789|QWERTZ
abc|ABC|1|QWERTZ
abc|ABC|0|QWERTZ
abc|ABC|123456789|QWERTZ

$ awk -F\| '$3 > 0 { print substr($3,1,6)}' file1
123456
1
123456

This User Gave Thanks to Scott For This Post:
Aia
# 3  
Old 09-06-2010
Code:
awk -F"|" '$3>0 { print substr($3,1,6)}'

This User Gave Thanks to pravin27 For This Post:
Aia
# 4  
Old 09-06-2010
thanks the awk worked
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