stout, stderr to syslog via function with if statement
I have a function called sysLogger in a bash script that I am using to redirect stdout and stderr to syslog.
Part of the script contains an option to turn on debugging otherwise I want debugging output to go to /dev/null.
I am struggling to understand how to make this work using the function I have created to take stderr and stdout and redirect it to syslog. Sending output to syslog works fine (although I am seeing file descriptor left open errors, not sure if they are a problem). But if I add an "if" statement to try and redirect any output to /dev/null depending on whether debugging is enabled I get "broken pipe" errors.
I have tried using "tee" and various other options to just redirect to /dev/null but none worked and googling about process substitution and file descriptors has made more confused than anything.
The full script and config file is attached so you can see what I am trying to do, but here is the important bits.
Function:
Code:
####### logging
sysLogger () {
local logPriority=$1
local logMessage=$2
case "${logPriority}" in
critical) logger -p local1.notice -t mugsyback.crit ${logMessage}
;;
warning) logger -p local1.notice -t mugsyback.warn ${logMessage}
;;
info) logger -p local1.notice -t mugsyback.info ${logMessage}
;;
debug) if "${logLevel}" = "debug" ; then
logger -p local1.notice -t mugsyback.debug ${logMessage}
else > /dev/null
fi
;;
*) echo "logging option does not exist"
;;
esac
}
Once example of output being redirected (altered for purposes of this post)
Edit: Sincere apologies, I have just realised I had not added "test" to the syntax. of the if statement. I have altered this post accordingly
Thanks, but it did not work for me.
I have created the following as a test script to simplify things.
I should also point out that the variable $logMessage is only used for manual entries into syslog otherwise the output from stderr and stdout is piped "into" logger.
e.g
Code:
sysLogger "info" "this text is added to syslog"
Code:
#!/bin/bash -x
logLevel=
####### logging
sysLogger () {
local logPriority=$1
local logMessage=$2
case "${logPriority}" in
critical) logger -t mugsyback.crit ${logMessage}
;;
warning) logger -t mugsyback.warn ${logMessage}
;;
info) logger -t mugsyback.info ${logMessage}
;;
debug) if test "${logLevel}" = "debug";
then
logger -t mugsyback.debug ${logMessage}
else
logger -t mugsyback.debug /dev/null
fi
;;
*) echo "logging option does not exist"
;;
esac
}
mount -v /mnt/backup 2> >(sysLogger "critical") 1> >(sysLogger "debug") || { echo "failed" ; exit 1 ; }
I get the following output (with bash -x)
Code:
[/C+ logLevel=
+ mount -v /mnt/backup
++ sysLogger critical
++ local logPriority=critical
++ local logMessage=
++ case "${logPriority}" in
++ logger -t mugsyback.crit
+ echo failed
failed
+ exit 1
A sample.c file is written with only one single statement.
main;
Segmentation fault occurred when executed that file.
Any statement other than main; is written, for example unix; then it won't compile.
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