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awk multiline with 1 or more variables (question)

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# 1  
Old 09-01-2010
awk multiline with 1 or more variables (question)
am trying to grab the fields marked in red for monitoring purposes. each vfiler can have anywhere from 0-50 Path(s).

in order to get here i run the following
Code:
for filer in `cat filers.list` ; do ssh $filer  vfiler status | awk '{print $1}' ; done

this returns
Code:
vfiler0
vfilert
vfiler2

based on this i would now ssh to each vfiler and do a vfiler status -r to find out what Paths are assigned to this vfiler, and then run ssh vfiler df -h for each Path (hoping i can do this all through awk)
so now the question is , the output is on multiple lines, how would i grab the blue (hostname) and red (Path) only ?
Code:
vfiler0                         running
   ipspace: default-ipspace
   IP address: 192.168.56.104 [ns0]
   IP address: 192.168.56.201 [ns1]
   Path: / [/etc]
   UUID: 00000000-0000-0000-0000-000000000000

vfilert                          running
   ipspace: default-ipspace
   IP address: 192.168.56.202 [ns0]
   Path: /vol/vfiler_vol [/etc]
   Path: /vol/virt_vol
   UUID: 87ae189e-b6c6-11df-ac98-00505614cd84

vfiler2                          running
   ipspace: default-ipspace
   IP address: 192.168.56.205 [ns1]
   Path: /vol/vfiler2_vol0 [/etc]
   UUID: f43ab782-b77b-11df-94a6-00505614cd84

Last edited by Scott; 09-01-2010 at 06:43 PM.. Reason: Added code tags
# 2  
Old 09-01-2010
something along these lines:
Code:
#!/bin/ksh
while read filer
do
  ssh $filer vfiler status | awk '{print $1}')
  ssh $filer vfiler status -r | awk '/^Path/{print substr($0, 1, index($0," [")-1)}'
done < filers.list

# 3  
Old 09-01-2010
Code:
 awk '/running/{host=$1}/Path:/{path=$2;print host,path}' filers.list

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