sed - replacing on the right of a pattern and looking for exact word?
how would you get SED to do the following, say you have the following lines in a text file:
user=tigger
some text some text
some text some text
some text some text
user=ted
some text some text
some text some text
some text some text
user=thekingofrockandroll
you want to find any line which has 'user=[the user name]' and replace it with 'user=xxx'
so the string after the 'user=' will always contain a different number of characters but you just want to sed to find any lines with 'user=' and replace the part after 'user=' with 'xxx' no matter what?
and...
if what to replace say 'AM' in a text file with 'JO', i can do:
but what if the text file where i'm running this looks like this:
AM
TAME
am
jammy
I only want to replace the following lines with 'JO':
AM
am
so I want to leave 'TAME' and 'jammy' in there - the sed above will give this:
JO
TJOE
jo
JJOMY
I want:
JO
TAME
jo
jammy
how do you achieve that with SED?
Cheers!
Last edited by rich@ardz; 09-01-2010 at 12:07 PM..
Reason: Code tags :)
hmm, what I would like ideally is this (say I'm replacing JO with BO)
my file to run sed on looks like this (as an example):
akdjfdkl sdjfklsjdf jsdfkljsf JO KSJDFKDFJLJOdsjfskldjf dsjfkljsfl <---- first JO on this line should be replaced by sed, second one should not because it forms part of a word
akdjalsd@JO <--- JO should be replaced here by sed
sdfkjdslfjsl@dfdsf_JO <----- and here JO <---- and here jo <----- and here
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apple
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---------- Post updated at 12:10 PM ---------- Previous update was at 12:01 PM... (11 Replies)
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For Ex:
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while read line
do
echo $line
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