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Using awk to print line starting with particular word

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# 1  
Old 08-26-2010
Using awk to print line starting with particular word
Hi Geeks,

Consider this line:

driver=c:\folder1\folder2

The above line is contained in a variable say 'var' . I want to copy everything after 'driver=' in to another variable say var2.

Please tell me how can this be done.
# 2  
Old 08-26-2010
Code:
$> var="driver=c:\folder1\folder2"
$> var2=${var#*=}
$> echo $var2
c:\folder1\folder2

This User Gave Thanks to zaxxon For This Post:
ajincoep
# 3  
Old 08-26-2010
Ha!

It's an awk question Smilie

Code:
$> var2=$(echo $var | awk -F= '{print $2}')

Last edited by Scott; 08-26-2010 at 10:50 AM.. Reason: Changed my PS1 :)
This User Gave Thanks to Scott For This Post:
ajincoep
# 4  
Old 08-26-2010
Pfff! SmilieSmilie
It's var2=... not $var2=...
# 5  
Old 08-26-2010
Thanks Guys
# 6  
Old 08-30-2010
Finally something not best done in awk! Smilie

The parameter substitution is much more slick.

Mike
# 7  
Old 08-31-2010
What you all are saying will return line after ("=")

But the line should be returned after ("driver=").
Any thoughts???
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