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Getting filename for Nth line pattern match

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# 1  
Old 08-26-2010
Getting filename for Nth line pattern match
Hi,

I have many scripts in particular directory. And few of the scripts have exit 0 in second line. Now i wanted to list out the scripts name which has the exit 0 in its second line

I tried many options , but i can not get the filename along with the nth line pattern match Smilie. Can anyone please help on this?

Thanks,
Puni
# 2  
Old 08-26-2010
Code:
awk 'NR==2&&/exit 0/ {print FILENAME}' infile

# 3  
Old 08-26-2010
You can try something like:
Code:
awk 'NR==2 && /exit 0/ {print FILENAME}' *.sh

If the scripts are scattered over some subdirectories you might want to feed awk with a find or recursive ls.
# 4  
Old 08-26-2010
Hi rdcwayx and zaxxon,

Thank you. If i specify the input file name its working fine. But if i give *.sh its not giving any output
I want to search in all the scripts, so i cannot specify the input filename

Thanks,
Puni
# 5  
Old 08-26-2010
Try:
Code:
awk '/exit 0/&&FNR==2{print FILENAME}' *.sh

# 6  
Old 08-26-2010
Hi Scrutinizer,

Thanks a lot. Now its working fine. But in some of the scripts has #exit 0. I want the scripts which has exit 0 only.That line should not have commented.

Is there anyway to omit the scripts which has #exit 0?

Thank you,
Puni
# 7  
Old 08-26-2010
How about this,
Code:
grep -n "exit 0" *.sh | perl -nle 'if (/(.*\.sh):2:/) {print $1}'
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