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Counting characters with sed

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# 1  
Old 08-22-2010
Counting characters with sed
Input:
Code:
ghw//yw/hw///??u

How can i count the slashes("/") using sed?
# 2  
Old 08-22-2010
Don't know how to do it in sed.. but here you have AWK and Perl:
Code:
awk -F"/" '{print NF-1}' file

Code:
perl -ne '@n=m/\//g;print $#n+1' file

# 3  
Old 08-22-2010
Using sed you still need to count, e.g.:
Code:
$ echo ghw//yw/hw///??u | sed s#[^/]##g | wc -L
6

This User Gave Thanks to Scrutinizer For This Post:
cola
# 4  
Old 08-22-2010
Quote:
Originally Posted by bartus11
Don't know how to do it in sed.. but here you have AWK and Perl:
Code:
awk -F"/" '{print NF-1}' file

Code:
perl -ne '@n=m/\//g;print $#n+1' file

Please explain the perl command.
# 5  
Old 08-22-2010
Match operator (m//) returns all the matched strings as array. So @n contains all the "/"s matched in current line. $#n is index of array's last element, and because Perl starts indexing from 0, we need to add "1" to get total number of elements in array, ergo total number of "/"s in current line.
This User Gave Thanks to bartus11 For This Post:
cola
# 6  
Old 08-22-2010
Quote:
Originally Posted by Scrutinizer
Using sed you still need to count, e.g.:
Code:
$ echo ghw//yw/hw///??u | sed s/[^/]//g | wc -L
6

Please explain the command.
# 7  
Old 08-22-2010
It removes all non-slash characters and then calculates the line length
This User Gave Thanks to Scrutinizer For This Post:
cola
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