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Splitting string with awk

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# 1  
Old 08-21-2010
Splitting string with awk
Input:
Code:
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How can i split this string with space(" ") and store words into array?
# 2  
Old 08-21-2010
Code:
awk '{for (i=1;i<=NF;i++) a[$i]++}END {for (i in a) print i,a[i]}' input

# 3  
Old 08-21-2010
Quote:
Originally Posted by rdcwayx
Code:
awk '{for (i=1;i<=NF;i++) a[$i]}' input

How to do this using FS" " (field seperator)?
# 4  
Old 08-21-2010
Quote:
Originally Posted by cola
How to do this using FS" " (field seperator)?
Your question doesn't make a whole lot of sense - if it did, you just answered it yourself.

You want to store this input in an array where? In AWK, or in the shell?
# 5  
Old 08-21-2010
Quote:
Originally Posted by scottn
Your question doesn't make a whole lot of sense - if it did, you just answered it yourself.

You want to store this input in an array where? In AWK, or in the shell?
Definitely awk string.
# 6  
Old 08-21-2010
There are punctuations in your string, so:
Code:
 awk -F"[ ,.]" '{for(i=1;i<=NF;++i) if($i!="")a[$i]} END {for(s in a) print s}' infile

If you insist on using FS, try this, it has the same output as the above code.
Code:
awk 'BEGIN {FS="[ ,.]"} {for(i=1;i<=NF;++i) if($i!="")a[$i]} END {for(s in a) print s}' infile

This User Gave Thanks to kevintse For This Post:
cola
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