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awk/sed percentage calculation

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# 1  
Old 08-20-2010
awk/sed percentage calculation
Hi all

i have a text file with columns delimited with ,

2010-08-18,10,24,.09751,39,7,14872,26732
.
.
.


i would to add a extra column in the end with percentage calculation of columns 5 and 8 ie (39/26732)*100

so the output must look like

2010-08-18,10,24,.09751,39,7,14872,26732,.14
.
.
.


Thanks
# 2  
Old 08-20-2010
Code:
awk  -F, '{printf "%s,%s",$0,substr($5/$8*100,2,3)}' urfile

2010-08-18,10,24,.09751,39,7,14872,26732,.14

This User Gave Thanks to rdcwayx For This Post:
posner
# 3  
Old 08-20-2010
thanks rdcwayx works great
# 4  
Old 08-20-2010
Please be careful, my code is not for Rounding.

If you need rounding (0.145893), it should be 0.15
# 5  
Old 08-20-2010
Quote:
Originally Posted by rdcwayx
Please be careful, my code is not for Rounding.

If you need rounding (0.145893), it should be 0.15

it shouldn't now as percentage is very low .14% and its gonna be same low % for rest of the file .

but it would be better if rounding is done in the script

thanks
# 6  
Old 08-20-2010
Somrthing like this,
Code:
awk  -F, '{printf "%s,%.2f\n",$0,($5/$8*100)}' infile

This User Gave Thanks to pravin27 For This Post:
posner
# 7  
Old 08-21-2010
Code:
# x=$(echo "`sed 's/.*\.[0-9]*,\([^,]*\).*/\1/' infile` * 10000 / `sed 's/.*,\([^,]*$\)/\1/' infile`" | bc | sed 's/^/,./') ; sed "s/$/$x/" infile
2010-08-18,10,24,.09751,39,7,14872,26732,.14

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