Hi,
Need help in understanding the behaviour of the find command.
I am writing a command to find out all the known errors in the log files and console files. That would help me in understanding the health of the application server. I have written the below command that would run a few execs' in the find command and return the count of the instances of those known errors.
So, as you see that, there are 5 such known errors that would impact the health of the application server.
I want the count of all 5 such known errors but the commands that I have written so far, doesnt return the count of the other instances once it finds the result in one of them.
e.g. 1 file, stops the execution at the 3 errors and doesnt return the count of the 4 and 5 errors.
2nd & 4th file, executes all the known errors because no error records were found in the file.
3rd file, stop the execution at the first error itself since the records are found there.
I have tried the "-o" and "-a" options. "-a" or no options executes only the first known-errors
In my opinion you are really overloading the find command. My inclination would be to let find simply locate the files, and then use a simple shell function to execute the search of the files. There isn't anything to be gained by driving the searches from find.
This script is completely untested, but should do what you want. It finds the files and then executes the search function for each. The search function echoes the search string and the count of that string in the file.
The function is only a convenience to avoid typing the search string twice, or having to directly assign it to a variable making the body of the script a bit easier to read.
Hello,
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Thanks in advance.
Regards
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