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Shell Programming and Scripting

Removing data with pattern matching

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# 1  
Old 08-13-2010
Removing data with pattern matching
I have the following:

HH:MM:SS

I want to use either % or # sign to remove :SS can somebody please provide me an example. I know how to do this in awk, but awk is too much
overhead for something this simple since I will be doing this in a loop a lot of times.

Thanks in advance to all who answer
# 2  
Old 08-13-2010
Code:
time=HH:MM:SS
echo ${time%???}

# 3  
Old 08-13-2010
Code:
# time="HH:MM:SS"

Code:
# echo ${time%*:*}
HH:MM

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