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cat arguments to a function

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# 1  
Old 08-10-2010
Question cat arguments to a function
Hi,

I've a logging function in bourne shell, flog() which logs the first argument passed to it. How can I pass arguments to this function from a file, like

Code:
cat filename | sed '...filtering...' | flog

or
Code:
cat filename | sed '...filtering...' | xargs flog

Which did not work, after which then I tried to use a while loop to feed the lines one by one to the function :

Code:
while read line
do
   flog "$line"
done < `cat filename | sed '...filtering...'  `

However the above method also did not work.

Finally I was able to do it by first creating the filtered file, then parsing it through the loop:

Code:
cat filename | sed '...filtering...'  > filename2 
while read line
do
   flog "$line"
done < filename2

Is there a more elegant way of doing this?
# 2  
Old 08-10-2010
Something like this?
Code:
sed '...filtering...' filename | while read line
do
  flog "$line"
done

# 3  
Old 08-10-2010
try this
Code:
while read line ; do
    flog "${line}"
done < <(sed '...filtering...'  filename)

# 4  
Old 08-10-2010
Question It works :)
Thanks,

Code:
sed '...filtering...' filename | while read line
do
  flog "$line"
done

Works perfectly Smilie

However this also works but at the end of printing it'll print an additional line telling file not found.
Code:
while read line ; do
    flog "${line}"
done < <(sed '...filtering...'  filename)

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