Shell Programming and Scripting

Hi,

I need help in writing shell script to accomplish the following.

1.I've one text file which contains list of batch numbers like b1.dat,b2.dat,b3.dat...

2.I've the same files along with other files present in some directory.i.e 1.dat,2.dat,3.dat,4.dat,5.dat... present in some directory.

3.I need to write shell script which will find the files present in the step1 text file under the directory of files in Step2 for every 1 hour and if the same files are found copy the files to some other location and delete the entry of that file in the step1 text file.

Please advise if any body has any solution.

Thanks,
Kumar

What have you tried so far?

I'm not 100% sure what you're asking for but I think you're saying you have a file structure that looks like:

directory
- 1.dat file
- 2.dat file
- b1.dat file
- b2.dat file

And you want to grab only the b{1,2}.dat ?

OR

Are you saying you want to see if b1.dat and 1.dat are alike and if they are just remove the b1.dat and keep the 1.dat (IF a similar file exists).

Really having a hard time understanding your requirements

---------- Post updated at 08:20 AM ---------- Previous update was at 08:20 AM ----------

I'm not 100% sure what you're asking for but I think you're saying you have a file structure that looks like:

directory
- 1.dat file
- 2.dat file
- b1.dat file
- b2.dat file

And you want to grab only the b{1,2}.dat ?

OR

Are you saying you want to see if b1.dat and 1.dat are alike and if they are just remove the b1.dat and keep the 1.dat (IF a similar file exists).

Really having a hard time understanding your requirements

Code:

CurDir=/PATH1
OtherDIR=/PATH2

cd $Curdir

for file in $(cat step1.text.txt)
do 
  if [ -f $OtherDIR/$file ] ; then
      cp $file $OtherDIR/$file
      rm $file 
  fi
done

test with sample files first, then put it in cronjob.