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Problem in storing value to variable

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# 1  
Old 08-06-2010
MySQL Problem in storing value to variable
Code:
#bash

curVer=`cat /var/sadm/clsversion | cut -f 2 -d "_"`
echo "CurVer:$curVer"
ls |grep -v tar| grep -v sh| grep -v log|cut -f 1  -d "_" | sort -u >tmp1
for line in $(cat tmp1)
do
        ver=`echo $line_$curVer`
        ls $line* |sort >tmp2
        grep -n ${ver} tmp2 >/dev/null
        if [ $? = "0" ]
        then

                grep -n ${ver} tmp2 | |cut -f 1 -d ":"

                ClineNo=`grep -n ${ver} tmp2 |cut -f 1 -d ":"`
                echo $ClineNo

  
        fi
done

Problem:

This line give correct output.
Code:
grep -n ${ver} tmp2 | |cut -f 1 -d ":"

Output:
Code:
28
14
14
14
14
22
14
14
27
54
68
82
27
14
14
14
14

But when i am trying to store the value to the variable, It stores 4 values in single variable.

Code:
ClineNo=`grep -n ${ver} tmp2 |cut -f 1 -d ":"`
echo $ClineNo

OutPut:
Code:
28
14
14
14
14
22
14
14
27 54 68 82
27
14
14
14
14

Kindly help in this regards.

Moderator's Comments:
Mod Comment Start using code tags please.
# 2  
Old 08-06-2010
try quoting:

Code:
echo "$ClineNo"

This User Gave Thanks to clx For This Post:
rajamohan
# 3  
Old 08-09-2010
Thanks anchal now is working fine...
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