Shell Programming and Scripting

Hi,

I have a problem that I am sure someone will know the answer to. Currently I have a script which returns a binary output if it finds a certain search string (in this case relating to a DRBD cluster) as follows:

Code:

searchstring="cs:Connected st:Primary/Secondary ds:UpToDate/UpToDate"
[ $(grep -c "$searchstring" /proc/drbd) -gt 0 ] && echo 1 || echo 0

What I need is to make a new script that will search for a string, but rather than searching a file, I want to search the last 10 lines of a file, and return 1 if its found and 0 if not. I guess I'll have to use tail but not sure of the syntax.

Thanks for any help!

use process substitution:-

Code:

[ $(grep -c "$searchstring" <( tail -10 /proc/drbd)  ) -gt 0 ] && echo 1 || echo 0

That easy huh? Thanks!

Out of interest, if I wanted to get it to search for multiple strings, what would be the best way of doing that? In other words to return 0 if nothing is found, but 1 if any of the strings are located in the tail-ed output.

use for loop:-


ex:-

Code:

for searchstring in "xxxxx" "ffffff" ...etc
do
[ $(grep -c "$searchstring" <( tail -10 /proc/drbd)  ) -gt 0 ] && echo 1 || echo 0
done